Question

The value of K for which the lines x=1,y=2 and k^2x+2y-20=0 are concurrent is

Answer 1

Answer:

k²×1+2×2-20=0

k²+4-20=0

k²+16=0

k²= -16

k=√16

k= -4

Answer 2

Step-by-step explanation:

kx²+2y-20=0

k(1)²+2(2)-20=0

k+4-20=0

k=16 Ans

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