Math, asked by shreyadutta436, 7 months ago

The value of k for
which the pair of equation
2x+ky=3 and 3x-2y=4
will have uniqe
solution will be-​

Answers

Answered by sandeepkumarbehar
1

Step-by-step explanation:

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Answered by pranavadithya32
1

Answer:

K NOT EQUAL TO -2

Step-by-step explanation:

2k+ky=3 and 3x-2y=4

For a unique solution condition = A1/A2 not equal to B1/B2.

Therefore;  A1=2K;A2=3 and B1=K;B2=-2

A1/A2=B1/B2---------> 2K/3 NOT EQUAL TO K/-2

------------> 3k not equal to 2k-2

therefore K NOT EQUAL TO -2

THEREFORE; ANY VALUE OF K EXCEPT -2 IS A UNIQUE SOLUTION.

PLSPLS PLSSS MARK AS BRAINLIEST

HOPE IT HELPED :)

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