Math, asked by pinki677, 9 months ago

the value of k for which the pair of equation kx-y=2 and 6x-2y=3 will have infinitely solution is​

Answers

Answered by Anonymous
2

Answer:

k=3

Step-by-step explanation:

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Answered by Sneha2538
1

Answer:

kx-y=2

6x-2y=3

multiplying eqn 1 with 2

2kx-2y=2

6x-2y=3

- + -

2kx+6x=-1

2x(k+3)=-1

2x=-1-k-3

2x=-4-k

k=-2x-4

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