the value of k for which the pair of equation kx-y=2 and 6x-2y=3 will have infinitely solution is
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2
Answer:
k=3
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Answered by
1
Answer:
kx-y=2
6x-2y=3
multiplying eqn 1 with 2
2kx-2y=2
6x-2y=3
- + -
2kx+6x=-1
2x(k+3)=-1
2x=-1-k-3
2x=-4-k
k=-2x-4
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