The value of K for which the quadratic equation 16x2 + 4kx + 9 = 0 has real and equal roots are Select one:
a. 4, -4
b. 5, -5
c. 6, -6
d. 9, -4
Answers
Answered by
1
Answer:
c 6,-6
Step-by-step explanation:
hope this is correct
Answered by
1
Step-by-step explanation:
Given : Equation 16x^2+4kx+9=016x
2
+4kx+9=0
To find : For what value of k equation has real and equal roots ?
Solution :
Discriminant, D=b^2-4acD=b
2
−4ac
Equal roots have discriminant zero,
b^2-4ac=0b
2
−4ac=0
On comparing 16x^2+4kx+9=016x
2
+4kx+9=0 with ax^2+bx+c=0ax
2
+bx+c=0
a=16 , b=4k and c=9
Substitute the values,
(4k)^2-4(16)(9)=0(4k)
2
−4(16)(9)=0
16k^2-576=016k
2
−576=0
16k^2=57616k
2
=576
k^2=\frac{576}{16}k
2
=
16
576
k^2=36k
2
=36
k=\pm 6k=±6
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