The value of 'K' for which the quadratic equation 2kx2 + x + 3 = 0 has equal roots, is
(a) 24 (b) 1/24
(c) -24
(d) - 1/24
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Answered by
0
Answer:
Step-by-step explanation:
Equal roots means that D = 0,
In the equation, a= 2k, b= 1 and c=3 and also D = 0 (given)
D = b^2 - 4ac
0 = (1)^2 - 4 (2k) (3)
0 = 1 - 24k
24k = 1
k = 1/24 Hence correct option is (b) i.e. 1/24.
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Answered by
0
2kx^2+x+3
It has equal roots..,so discriminant D=0
D=b^2-4ac
(In the given equation.., a=2 , b=1 , c=3)
(1)^2-4(1)(3)=0
1-24k=0
-24k=-1
K=-1/-24
Therefore k=1/24
Option (b) is correct
Hope this helps you.. :)
It has equal roots..,so discriminant D=0
D=b^2-4ac
(In the given equation.., a=2 , b=1 , c=3)
(1)^2-4(1)(3)=0
1-24k=0
-24k=-1
K=-1/-24
Therefore k=1/24
Option (b) is correct
Hope this helps you.. :)
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