Question

the value of k for which the quadratic equation is x2-2kx+5k =0 has real root are

Answer 1

for real roots discriminant of equation should be greater than zero

$d \geqslant 0 \\ 4 {k}^{2} - 20k \geqslant 0 \\ k(4k - 20) = 0 \\ k = 0 \: and \: 5$


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Answer 2

${ Hey Dear }$


Here is your answer


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x² - 2kx + 5k = 0


real roots = b² - 4ac <0


a = x² b = -2kx c = 5k


we apply b² - 4ac


( -2k)² - 4* 1 * 5


4k² -20 K = 0

K ( 4k - 20 ) = 0


4 K = 20

K = 20 / 5

K = 5


hence the value of K = 0 , 5

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