Math, asked by ayushom7518989, 15 hours ago

The value of k , for which the roots of x^2+kx-1=0 are real and unequal is​

Answers

Answered by BeAuTyBLusH
2

Answer:

Given x

2

+kx+k

roots are real & equal

∴b

2

−4ac=0

=(k)

2

−4(1)(k)=0

=k

2

−4k=0

=k(k−4)=0

∴ k = 0 or k = 4

Attachments:
Answered by мααɴѕí
2

Answer:

Given x

2

+kx+k

roots are real & equal

∴b

2

−4ac=0

=(k)

2

−4(1)(k)=0

=k

2

−4k=0

=k(k−4)=0

∴ k = 0 or k = 4

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