Question

The value of k for which the system has x+y-5=0

and 3x+ky=7 has no solution is .​

Answer 1

Answer:

k=3

Step-by-step explanation:

first of all when the condition is given that there should be no solution for the 2 equations hence the lines should be parallel to each other.

so we solve by adding these and eliminating the value of x and following by y.

X+y=5 (equation 1)

3x+ky=7(equation 2)

so now to eliminate x we need to multiply with -3 on both sides with equation 1. we get

-3x-3y=-15

add this to equation 2

-3x-3y=-15

+ 3x+ky=7

-------–----–------–--

0x+(k-3)y=-8

hence if k=3 then there will be no solution to this equations.

Answer 2

Answer:

Refer to the above attachment