Question

The value of k for which the system of equation 2x+KY=8 and x+y=6 have no solution

Answer 1

Answer:

2

Step-by-step explanation:

Answer 2

For the value of k = 2, the system of equation 2x+ky=8 and x+y=6 have no solution.

The system of expressions are:

2x + ky = 8 and x + y = 6

First expression is 2x + ky - 8 = 0

and second expression is x + y - 6 = 0

If we compare both the expressions with a₁x + b₁y - c₁ = 0 and a₂x + b₂y - c₂ = 0, respectively then

a₁ = 2, b₁ = k, c₁ = 8 and,

a₂ = 1, b₂ = 1, c₂ = 6

Then, for equations with no solutions, we have:

a₁/a₂ = b₁/b₂ = c₁/c₂

⇒ Taking only the first two equalities, we have:

2/1 = k/1

⇒ k =2