Question

The value of K for which the system of equation Kx+2y-y=0 and 2x+4y-12=0 have no solution, is ---
(a) 1 (b) 2 (c) 3 (d) 0 ​

Answer 1

x − 3y − 3 = 0,  x − 3y − 3 = 3x − 9y − 2 =

0, 3x − 9y − 2 = 0

Solution:

The given system may be written as

x − 3y − 3 = 0 

3x − 9y − 2 = 0

The given system of equation is of the form

a2x + b2y − c2 = 0 a2x + b2y − c2 = 0

Where, a1 = 1, b1 = −3, c1 = −3

a2 = 3, b2 = −9, c2 = −2

We have,

Therefore, the given equation has no solution.

so the answer is option d) 0