Question

The value of K for which the system of equation kx+3y = 12 x-y=1 has a unique solution is....?​

Answer 1

Step-by-step explanation:

See this attachment..

Hope its help..

Answer 2

Step-by-step explanation:

Comparing (k−3)x+3y=k with a

1

x+b

1

y+c

1

=0,

and kx+ky=12 with a

2

x+b

2

y+c

2

=0,

we get, a

1

=(k−3),a

2

=k,b

1

=3,b

2

=k

Now,

Given system of equations has unique solution

⇒

a

2

a

1



=

b

2

b

1

k

(k−3)



=

k

3

⇒k

2

−3k



=3k

⇒k

2



=6k

⇒k

2

−6k



=0

⇒k(k−6)



=0

⇒k



=0 and k



=6

So k



=6 is the correct option among given options.