Math, asked by Dhruvsharma1, 1 year ago

the value of K for which the system of equation kx-y=2and 6x-2y=3 has a unique solution is

Answers

Answered by Asdfghjkl123456789
7
Kx-y-2=0
6x-2y-3=0
A1=K ,B1=-1 ,C1=-2
A2=6 ,B2=-2,C1=-3
Condition for unique solution
A1/A2 ≠ B1/B2
K/6 ≠-1/-2
K/6≠1/2
K≠1/2*6
K≠3
Hence the value of K is other than 3
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