Question

The value of ‘k’ for which the system of equation kx-y = 2and 6x-2y=3 has a unique
solution is

(a) k=0​

Answer 1

Answer:

k ≠3

Step-by-step explanation:

kx-y=2

6x-2y=3

k/6≠ 1/2            (condition:a1/a2 ≠ b1/b2)

2k≠ 6

k ≠6/2

k≠3

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