Question

The value of k for which the system of equation x+2y-3=0 and 5x+ky-7=0 has no solution is

Answer 1

Answer:

10

Explanation:

For no solution

a1/a2 = b1/b2 not equal to c1/c2

Here,

a1 = 1

a2=5

b1=2

b2=k

c1=-3

c2=-7

So,

1/5=2/k

k=10

And 2/k not equal to -3/-7 which is also true

so value comes to be 10

Answer 2

Answer:

The condition for no solution is

a1/a2 = b1/b2 not equals to c1/c2,

so,

a1 = 1 , a2= 5 , b1= 2 , b2 = k

1/5 = 2/k,

now,

k = 10 (cross multiplication)