Question

the value of k for which the system of equation x+2y-3=0 and 5x+ky+7=0 has no solution is​

Answer 1

Answer:

k = 10

Step-by-step explanation:

a1 = 1. a2 =5

b1 = 2. b2 =k

C1 = -3. c2= 7

a1/a2 = 1/5

b1/b2 = 2/k

1/5 = 2/k

so, k =10