the value of k for which the system of equation x+y-4=0 and 2x+ky=3 has no solution is ?
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Answer:
a1/a2 =b1/b2≠c1/c2
and from equation a1 =1,b1=1,c1=-4
a2=2,b2=k,c2-3
so, 1/1=1/k≠-4/-3
by evaluating ,k=1
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