Math, asked by AnandiSiri5996, 8 months ago

The value of k for which the system of equations 2x+3y=5,4x+ky=10. has the infinity number of solution

Answers

Answered by Charviejindal
2

Answer:

K=6

Step-by-step explanation:

2x+3y=5

4x+ky=10

2/4=3/k=5/10

First:

2/4=3/k

Cross multiplying

2k=12

K=12/2

K=6

Secondly:

3/k=5/10

30=5k

30/5=k

K=6

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