Question

The value of k, for which the system of equations(K-1) x + (k +3)y = -1 and 15x + 3y = 3 has infinitely many solutions is * -3 -4 -5 None of these

Answer 1

Step-by-step explanation:

the value of k is 2 ...

hope this will help you...

Answer 2

Answer:

• Value of 'k' is -4

Explanation:

Given

Two linear equation in two variables are given,

• (k-1) x + (k+3) y = -1  and
• 15 x + 3 y = 3

To find

We need to find value of 'k'

Knowledge required

So, As we know

Two linear equation in two variable, Let

a₁x + b₁y = c₁  and  a₂x + b₂y = c₂

will have infinitely many solutions if,

• a₁/a₂ = b₁/b₂ = c₁/c₂

Solution

Comparing (k-1) x + (k-3) y = -1 and 15 x + 3 y = 3 with a₁x + b₁y = c₁ and a₂x + b₂y = c₂

we will get,

• a₁ = (k-1) , a₂ = 15
• b₁ = (k-3) , b₂ = 3
• c₁ = -1 , c₂ = 3

Further,

→ a₁ / a₂ = b₁ / b₂ = c₁ / c₂

→ (k-1) / 15 = (k+3) / 3 = -1 / 3

so,

→ (k+3) / 3 = -1 / 3

→ 3 k + 9 = -3

→ 3 k = =12

→ k = -4

Therefore,

• Value of 'k' is -4.