Question

The value of k for which the system of equations
kx+3y = 5
4x + y = 10
has infinite number of solutions, is
1
3
2.
0​

Answer 1

Answer:

Given equations are 2x+3y−5=0 and 4x+ky−10=0

Then 2x+3y−5=0⇒2x+3y=5

4x+ky−10⇒4x+ky=10

∴

4

2

=

k

3

=

10

5

.... [Since, they have an infinite number of solutions]

⇒

2

1

=

k

3

=

2

1

⇒

2

1

=

k

3

⇒k=6