Question

The value of k for which the system of equations X+2y-3=0 and 5x+KY+7=0 has no solution is.

Answer 1

Given:

The system of equations X+2y-3=0 and 5x+KY+7=0 has no solution.

To find:

The value of K.

Solution:

1) It is given that the given pair of the equation has no common solution so the given equations of the lines are parallel to each other.

2) The ratios of the parallel lines are given by:

• a1/a2 = b1/b2

So by putting the coefficients we get:

• 1/5 = 2/K

on solving we get

• K =10

The value of K is 10