Math, asked by djd21498, 8 months ago

The value of k for which the system of equations x + 2y = 5 ; 3x + ky + 15 = 0 has no solution​

Answers

Answered by diya2346
4

answer:

x+2y=5

x+2y-5=0 ------(1)

3x+ky+15=0----(2)

comparing equation (1) and (2)

u have to multiply equation (1) with 3

3x+6y-15=0

3x+ky+15=0

-__-________

6y - Ky =0

6-k= y -------(3)

put equation (3) in equation (1)

u can solve by eliminating method

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