The value of k for which the system of equations x + 2y = 5 ; 3x + ky + 15 = 0 has no solution
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answer:
x+2y=5
x+2y-5=0 ------(1)
3x+ky+15=0----(2)
comparing equation (1) and (2)
u have to multiply equation (1) with 3
3x+6y-15=0
3x+ky+15=0
-__-________
6y - Ky =0
6-k= y -------(3)
put equation (3) in equation (1)
u can solve by eliminating method
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