The value of k for which the system of equations x+y-4=0 & 2x+ky=3, has no solution, is
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Answer:
k=2
Step-by-step explanation:
x+y=4......... (1)
2x+ky=3.......(2)
if second is x+k/2=3/2
so compared by 1 st equation
k is not equal to 2
so k will not be 2
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