Question

The value of k for which the system of equations x+ y – 4 = 0 and 2x + ky = 3, has no solution, is

Answer 1

Answer:

Given ;

X+Y-4= 0

2X+KY -3=0

so. A1= 1,B1= 1,C1= -4

A2=2,B2= k,C2 = -3.

Step-by-step explanation:

let ,A1= 1,B1=1,C1= -4

A2= 2,B2= k, C2= -3

now, as it has no solution ;

we can say that ; A1/A2= B1/B2 is not equals C1/ C2.

in case 1: A1/ A2= B1/ B2

= 1/2=1/K

= K= 2(ans).

hence ,value of k =2.