the value of K for which the system of equations x+y-4=0 and 2x+ky=3 has no solution is
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Answered by
5
Answer:
no solution
so,a1/a2=b1/b2≠c1/c2
here a1=1,a2=2,b1=1,b2=k,c1=-4 and c2=-3
1/2=1/k
so,k=2
hope it helps!
Answered by
2
Answer:
here's your answer.
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k = 2...
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Step-by-step explanation:
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hope it helps you
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