Question

the value of k for which the system of linear equation
$x + 2y - 3 = 0$
and
$5x + ky + 7$
no having no such solution is​

Answer 1

Step-by-step explanation:

x+2y=3

5x+ky+7=0

x+2y=3

x+2y-3=0

x=-2y+3

put in the following equation

5(-2y+3)+ky+7=0

-10y+15+ky+7=0

solve this u get urs answer perfectly

Answer 2

ANsweR❤

For a system of equations a1x+b1y+c1=0;a2x+b2y+c2=0  to have no solution, the condition to be satisfied is

a2a1=b2b1=c2c1

⇒51=k2=7−3

∴ For k=10, the given system of equation has no solution.