Question

the value of k for which x=-2 is root of quadratic equation kx^2+x-6=0​

Answer 1

Step-by-step explanation:

x=-2

kx^2+x-6=0

substitute x=-2 in the equation

kx^2+x-6=0

k(-2)^2 +(-2)-6= 0

4k -2 -6= 0

4k -8= 0

4k = 8

k = 2

Answer 2

Answer:

l

Step-by-step explanation:

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