Question

The value of k for which x=2is a root of the quadratic eqation kx*x+x-6=0is

Answer 1

Answer:

Step-by-step explanation:

Kx×x+x-6=0

Put x=2

K(2)(2)+(2)-6=0

4K + 2 - 6 = 0

4K - 4 = 0

4K = 4

K = 1

Answer 2

Answer:

1

Step-by-step explanation:By factor theorem x = 2 be the root of the quadratic equation k x*x + x - 6 = 0

p(x) = kx*x + x -6 = 0

p(2) = k(2)(2) + 2 -6 = 0

  = 4 k -4 = 0

  = 4 k =4

  k= 1