Question

The value of k for which x^6-k is completely divisible by X-1​

Answer 1

let p(x)= x⁶‐k

g(x)= x-1

g(x) = 0

x+1= 0

x=-1

By remainder Theorem

p(x)= x⁶-k

p(-1)= (-1)⁶-k

= 1-k

k=1

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