the value of k for whick the equation is 2x^-kx+k=0 has equal roots is _______
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PrernaSharma:
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2x²-kx + k = 0
a = 2
b = -k
c = k
it has equal roots so
D = 0
b² - 4ac = 0
(k)² - 4 (2)(k)=0
k² - 8k = 0
k(k- 8) = 0
1st case
k (k -8) = 0
K = 0
2nd case
k (k-8) = 0
k -8 = 0
k = 8
k cannot be zero so
k = 8
a = 2
b = -k
c = k
it has equal roots so
D = 0
b² - 4ac = 0
(k)² - 4 (2)(k)=0
k² - 8k = 0
k(k- 8) = 0
1st case
k (k -8) = 0
K = 0
2nd case
k (k-8) = 0
k -8 = 0
k = 8
k cannot be zero so
k = 8
Right
thkss
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