The value of k if p(1) for p(y) = 3y⁴ -2y³+15y+k is -1
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Required Answer:-
Given Information:
- p(y) = 3y⁴ - 2y³ + 15y + k
- p(1) = -1
To Find:
- The value of k.
Solution:
It's given that -
→ p(1) = -1
So, put y = 1 in p(y).
→ p(1) = 3 × (1)⁴ - 2 × (1)³ + 15 × (1) + k
→ p(1) = 3 - 2 + 15 + k
→ p(1) = k + 16
Now, we know p(1) = -1,
→ k + 16 = -1
→ k = -1 - 16
→ k = -17
• So, the value of k is -17.
Answer:
- k = -17.
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