Question

the value of k if x+1 is a factor of (2xsqu + k x)​

Answer 1

Step-by-step explanation:

k+1=0

k=-1

(2x²+kx)

2(k+1)²+kx

2(k²+kx+1)+kx

2k²+3k+1

2k²+2k+k+1=0

2k(k+1)+1(k+1)=0

k=-1

k=-1/2 OK friend this is urs answer

Answer 2

Given ,

x + 1 is a factor of 2(x)² + kx

Let ,

P(x) = 2(x)² + kx

Since , it is a factor of x + 1

Thus ,

P(-1) = 0

2(-1)² + k(-1) = 0

2 - k = 0

-k = -2

k = 2

$\sf \therefore \underline{The \: value \: of \: k \: is \: 2}$