Math, asked by mahisingh8088, 10 months ago

The value of k, if (x +1) is a factor of 5x3 + 3x2 – 4kx+2, is

Answers

Answered by AlluringNightingale
0

Answer:

k = 0

Note:

★ If x-a is a factor of the polynomial p(x) , then x = a is its zero and hence f(a) = 0 .

Solution:

Let the given polynomial be p(x) .

Thus,

p(x) = 5x³ + 3x² - 4kx + 2

Also,

It is given that , x + 1 is a factor of the given polynomial .

Now,

If x + 1 = 0 , then

x = -1 .

Thus,

=> p(-1) = 0

{ °.° x + 1 is factor => x = -1 is a zero }

=> 5(-1)³ + 3(-1)² - 4k(-1) + 2 = 0

=> -5 + 3 + 4k + 2 = 0

=> 4k = 0

=> k = 0

Hence,

The required value of k is 0 .

Answered by MisterIncredible
5

 \Huge{\underline{\underline{ANSWER}}}

Given :

  {Cubic \:  expression = 5{x}^{3}+3{x}^{2}-4kx+2}

 \longrightarrow{Factor \: of \: the \: expression \: is \: (x + 1) }

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Required to find :

  1. Value of " k " ?

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Condition used :

Factor theorem

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Explanation :

Before solving this question we need to know some content about it .

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What is a polynomial ?

A polynomial is an expression which consists of variables , coefficient generally seperated by mathematical operations such as addition or subtraction or multiplication or with non negative integral powers .

 {Example :  {x}^{2} - x + 6}

Depending upon of the powers they are further divided ;

Mostly we talk about only 2

  1. Quadratic expression
  2. Cubic expression

Here is the example for each

Example of a quadratic expression

 \longrightarrow{{x}^{2}+7x+12}  \: \: is \: an \: quadratic \: expression

Similarly,

Example of a Cubic expression

 \longrightarrow{{z}^{3}-4z+4} \:  \:  \:  is \: an \: cubic \: expression

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What is a factor ?

A factor is considered to be as the multiple of the polynomial expression .

when this factor is substituted in the polynomial it gives us the remainder as zero .

When this factor value is substituted in the expression we have to do some operations by transferring the terms once it is gone .

The result is the value of K .

knowing this content is essential to solve these questions .

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Solution :

Consider the given cubic expression !

\longrightarrow{5{x}^{3}+3{x}^{2}-4kx+2}

Factor of the cubic expression is (x + 1)

So, let consider

 {x  + 1 = 0 }  \\  \boxed{\implies{ x \:  =  - 1}}

Now,

 p(x) = 5{x}^{3} + 3{x}^{2} - 4kx + 2

Now, substitute the value of X here

So,

  p(-1) = 5{(-1)}^{3} + 3{(-1)}^{2} - 4k(-1) + 2

 5(-1) + 3(1) - 4k(-1) + 2 = 0

  -5 + 3 + 4k + 2 = 0

 - 5 + 5 + 4k = 0

\cancel{ - 5 }\cancel{ + 5} + 4k = 0

-5 and 5 gets cancelled on both sides

4k = 0 \\ k =  \dfrac{0}{4}

As we know that any number which divides zero is also zero .

k \:  =  0

Hence,

 \boxed{\huge{\therefore{Value \:  of  \: k  \:  =  0}}}

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✅ Hence solved ..

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