Question

the value of k if (x+1) is a factor of x⁸+kx³- 2x+1 is​

Answer 1

Answer:

Step-by-step explanation:

Given if (x+1) is a factor of the equation, then on putting value of x = -1 it will satisfy the equation.

Therefore putting x=-1 in $x^8+kx^3- 2x+1$, we should get $x^8+kx^3- 2x+1$ = 0

$(-1)^8+k(-1)^3- 2(-1)+1 = 0$

So, 1-k+2+1 = 0

Therefore, k =4