Question

the value of k in which the equation 2x²+8kx+8=0 has equal roots​

Answer 1

Answer:

1

Step-by-step explanation:

b^2 -4ac=0

(8k)^2 - 4(2)(8)

(64k)^2-64=0

64k^2=64

k^2=64/64

k^2=1

therefore, k=1