Question

The value of k, so that quadratic equation 2x2 + kx + 3 = 0 has two equal roots.
(a) 2/6 (b) ± 256 (C) ± 2/3 (d) none of these​

Answer 1

Answer:

See below

Step-by-step explanation:

When we put D=0

B^2 - 4AC = 0

K^2 - 4×2×3 = 0

K^2 = 24

K = root 24

K = 2root6

Therefore the answer is

: None of these

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Answer 2

Correct answer: Option (d) none of these

Formula: We consider a quadratic equation of the form ax² + bx + c = 0. This equations will have equal roots when the discriminant be 0 (zero).

i.e., b² - 4ac = 0

Solution: Here the given equation is

2x² + kx + 3 = 0

Comparing the above equation with the general form of quadratic equation, we get

a = 2, b = k and c = 3

So discriminant = b² - 4ac

= k² - (4 * 2 * 3)

= k² - 24

For equal roots, discriminant = 0

Then k² - 24 = 0

or, k² = 24

or, k = ± 2√6

∴ Option (d) none of these is the correct answer.

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