Math, asked by harini678, 1 year ago

the value of k so that
 {x}^{2}  + 5kx + 16 = 0
has no real root

Answers

Answered by NishantMishra3
0
Discriminant=0

 { {b}^{2}  - 4ac}  = 0 \\  \\  {25 {k}^{2} -  64}  = 0 \\  \\ 25 {k}^{2}  = 64 \\  \\ 5k = 8 \\  \\ k =  \frac{8}{5}

harini678: sry that was not for u it was for that Aryan
harini678: I don't
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