Question

the value of k so that the quadratic equation
$2x + kx + 3 = 0$
has equal roots are
​

Answer 1

Answer:

2√6

Step-by-step explanation:

For equal roots,

d = 0

b^2-4ac = 0

k^2-4x2x3 = 0

k^2-24 = 0

k^2 = 24

k = √24

k = 2√6

Answer 2

Answer:

Answer:a=2,b=k,c=3

Answer:a=2,b=k,c=3 now,

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24k2=24

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24k2=24k=√24

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24k2=24k=√24k=√4*6

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24k2=24k=√24k=√4*6k=2√6

Answer:a=2,b=k,c=3 now,b2(here 2 is a square)-4ac=0 ----(given)(k)2-4*2*3=0(k)2-24=0k2=0+24k2=24k=√24k=√4*6k=2√6