Question

the value of 'k' so that the system of equations 3x-y-5=0 and 6x-2y-k=0 have infinitely many solutions is​

Answer 1

Answer:

Here, The value of k is 10.

Step-by-step explanation:

Here, As per our given question,

=Both equations have infinitely many solutions,

So, their form would be =a1/a2=b1/b2=c1/c2

Now, a1=3, a2=6, b1=(-1), b2=(-2), c1=(-5), c2=(-k)

Now, We would solve it as, (a1/a2=b1/b2), (b1/b2=c1/c2)

=3/6=(-1)/(-2) , (-1)/(-2)=(-5)/(-k)

=1/2=1/2 , 1/2=5/k

, 10=k [On cross-multiplying]

So, here the value of k=10.

Thank you.