Math, asked by Varadnb151, 7 months ago

The value of k so that the system of equations 3x-y-5=0and 6x-2y-k=0have infinitely many solutions is

Answers

Answered by jitendertypist702
0

Answer:

infinitely many solutions.

Answered by tyrbylent
0

Answer:

k = 10

Step-by-step explanation:

System of equations

y = m_{1} x + b_{1}

y = m_{2} x + b_{2}

has infinitely many solutions if m_{1} = m_{2} and b_{1} = b_{2}

~~~~~~~~~~~~

Solve 3x - y - 5 = 0 and 6x - 2y - k = 0 for "y"

3x - y - 5 = 0 ⇒ y = 3x - 5

6x - 2y - k = 0

2y = 6x - k ⇒ y = 3x - \frac{k}{2}

\frac{k}{2} = 5 ⇒ k = 10

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