Question

- The value of k such that 2 cosec 30° + k sin^2 60° -3/4 tan^2 30º = 10, is​

Answer 1

Answer:

$k = 11.$

Step-by-step explanation:

$2 \csc(30) + k( { \sin(60) }^{2} ) - \frac{3}{4} { \tan(30) }^{2} = 10 \\ \\ 2(2) + k( {( \frac{ \sqrt{3} }{2})) }^{2} - \frac{3}{4} {( \sqrt{3}) }^{2} = 10 \\ \\ 4 + k \frac{3}{4} - \frac{9}{4} = 10 \\ \\ \frac{16 + 3k - 9}{4} = 10 \\ \\ 3k + 7 = 40 \\ \\ 3k = 33 \\ \\ k = 11.$