Question

The value of k such that 3x2+2kx-k-5 has the sum of the zeroes as half of their product is a. 2/3 b. 5/3 c. 7/3 d. 8/3

Answer 1

Step-by-step explanation:

the answer will be 3x²+2kx-k-5

alpha +beta =-b/a=-2k/3

alpha x beta =c/a=-k-5/3

sum=1/2xproduct

-2k/3=1/2x-k-5/3

-2k/3=-k-5/6

-2k=-k+5

-2k+k-5=0

-k=5 the answer will be suppose 5/3 OK friend

Answer 2

Answer:

the right answer is 5/3

thank you

Step-by-step explanation: