Math, asked by ammeenaanita, 9 months ago

The value of k when 3k+2, 4k+3 & 6k-1 are in AP

Answers

Answered by hitmanbro
1

Answer:

value of k is 1 in this AP

Answered by meghana200631
1

Answer:

k=1

Step-by-step explanation:

common Difference=a2-a1

4k+3-(3k+2)

4k+3-3k-2

k-1=0

k=1

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