The value of k when 3k+2, 4k+3 & 6k-1 are in AP
Answers
Answered by
1
Answer:
value of k is 1 in this AP
Answered by
1
Answer:
k=1
Step-by-step explanation:
common Difference=a2-a1
4k+3-(3k+2)
4k+3-3k-2
k-1=0
k=1
Similar questions