the value of k when the roots of equation x2-kx+25=0 are equal
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Answered by
4
Answer:
Sorry, this will never happen as a quadratic equation always has two roots. However, these roots may have the same value, which is what you really want.
Consider the generic quadratic equation: ax2+bx+c=0
Do you recall the formula for finding the roots of this equation?
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…
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x=−b±b2−4ac√2a
For the roots to be identical, the radical part must be zero, thus we require:
b2=4ac
From your equation, b=k , a=1 and c=25 , thus:
k2=4×25=100⇒k=±10
Answer: k = ±10
Should apply… D=0=>
k^2–4*25=0=>
k=+/- 2*5=+/-10
Answered by
3
Answer:
k =√200 or k= 10√2
Step-by-step explanation:
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