Question

The value
of
K when (x –1) is a factor of
2xsquare + kx + √2 =0​

Answer 1

Answer:

K= √2 (1 - √2) or √2 (√2- 1)

Step-by-step explanation:

Put, K=1 (given that (X-1)

Now,

2 (1)^2 + K (1) + √2 =0

2 (1*1) + K+ √2 =0

2 + K + √2 =0

2+K = √2

K= √2-2 or √2 (1 -√2)

Or

K= 2- √2 or √2 (√2-1)