Question

the value of k which(-4) is a zero of the polynomial x2-x-(2k+2) is​

Answer 1

k= 9

Step-by-step explanation:

If (-4) is a zero of the polynomial..then,

p(-4)=x²-x-(2k+2)=0

=(-4)²-(-4)-(2k+2)=0

=16+4-2k-2=0

=20-2-2k=0

=18-2k=0

= -2k=0-18

=k=(-18)/(-2)

=k=9

Answer 2

Step-by-step explanation:

Since -4 is a zero of the given equation,

x= -4

Substituting the value of x in the equation

• x^2 -x -(2k + 2) = 0

• (-4)^2 - (- 4 ) - (2k + 2) = 0

Opening all brackets,

• (-4 *- 4) + 4 – 2k - 2=0

• 16 + 4 – 2– 2k = 0

• 20 – 2 – 2k = n0

• 18 – 2k =n0

• -2k = -18

• k= -18 / -2

• k=9