the value of k will the consecutive terms 2k +1 , 3k+3 , 3k-1 f
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Hello!
∵ 2k + 1, 3k + 3, 3k - 1 are consecutive terms.
∴ d₁ = d₂
Then,
3k + 3 - (2k + 1) = 3k - 1 - (3k + 3)
⇒ 3k + 3 - 2k - 1 = 3k - 1 - 3k - 3
⇒ k + 2 = - 4
⇒ k = - 4 - 2 ⇒ k = - 6
Cheers!
∵ 2k + 1, 3k + 3, 3k - 1 are consecutive terms.
∴ d₁ = d₂
Then,
3k + 3 - (2k + 1) = 3k - 1 - (3k + 3)
⇒ 3k + 3 - 2k - 1 = 3k - 1 - 3k - 3
⇒ k + 2 = - 4
⇒ k = - 4 - 2 ⇒ k = - 6
Cheers!
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