Question

The value of kc for the following equilibrium is Caco3
Caocs+ Co2cg). Given kp = 167 bar at
1073K​

Answer 1

Answer:

1.896

Explanation:

CaCO  

3

​  

(s)⇌CaO(s)+CO  

2

​  

(g)

Δn=(0+1)−0=1

K  

c

​  

=  

(RT)  

Δn

 

K  

p

​  

 

​  

 

K  

c

​  

=  

(0.0821Lbar/K)×(1073K)

167bar

​  

=1.896mol/L