Question

The value of kk for which the system of equation x+2y-3=0x+2y−3=0 and 5x+ky+7=05x+ky+7=0 has no solution, is​

Answer 1

Answer:

Thus for all real values of k other than 10, the given system of equations will have a unique solution. Hence, the required value of k is 10. There is no value of k for which the given system of equations has an infinite number of solutions.

Step-by-step explanation:

✌️✌️✌️✌️✌️

Answer 2

Answer:

good morning ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❤️❤️❣️❤️❤️❣️❤️❤️❤️❣️✨✨❤️❣️❤️❣️❤️❤️❤️