Question

The value of kp for the reaction Br2(l) + Cl2(g) = 2BrCl(g) at 27°C is '1 atm'. At equilibrium in a closed container partial pressure of BrCl gas is 0.1 atm and at this temperature the vapour pressure of Br2(l) is also 0.1 atm. Then what will be minimum moles of Br2(l) to be added to 1 mole of Cl2 initially, to get above equilibrium situation

Answer 1

Answer:

The value of kp for the reaction Br2(l) + Cl2(g) = 2BrCl(g) at 27°C is '1 atm'. At equilibrium in a closed container partial pressure of BrCl gas is 0.1 atm and at this temperature the vapour pressure of Br2(l) is also 0.1 atm. Then what will be minimum moles of Br2(l) to be added to 1 mole of Cl2 initially, to get above equilibrium situation?