Question

the value of Kw is 9.5 * 10to power -14 at a certain temperature , calculate the pH of water at this temperature ?

ans: 6.51

Answer 1

Kw = Ka × Kb
Kw = Ka²
Ka = √Kw
= √(9.5 × 10^-14)
= 3.08 × 10^-7

pH = -log(Ka)
= -log (3.08 × 10^-7)
= 6.51

pH of water at that temperature is 6.51